[tex]\displaystyle\lim_{ \sf \: x \to \frac{1}{5} } [x + 8 - 4 \times 12][/tex]
...........
[tex]\displaystyle\lim_{\begin{array}{c}x\to\frac{1}{5}\end{array}}\left(x+8-4\times 12\right)=\bf{-}39\,\frac{4}{5}[/tex]
atau
[tex]\displaystyle\lim_{\begin{array}{c}x\to\frac{1}{5}\end{array}}\left(x+8-4\times 12\right)=\bf{-}\frac{199}{5}[/tex]
PEMBAHASAN
Limit
[tex]\begin{aligned}&\lim_{\begin{array}{c}x\to\frac{1}{5}\end{array}}\left(x+8-4\times 12\right)\\&...\textsf{ bukan bentuk tak tentu}\\&...\textsf{ maka langsung substitusi saja}\\&{=\ }\frac{1}{5}+8-48\\&{=\ }\frac{1}{5}-40\\&{=\ }\boxed{\ \bf{-}39\,\frac{4}{5}\ }\\&{=\ }\boxed{\ \bf{-}\frac{199}{5}\ }\end{aligned}[/tex]
[tex]\displaystyle\lim_{ \sf \: x \to \frac{1}{5} } [x + 8 - 4 \times 12][/tex]
[tex] \frac{1}{5} + 8 - 48[/tex]
[tex] \frac{1}{5} + \frac{8}{1} - \frac{48}{1} [/tex]
[tex] \frac{1}{5} + \frac{8 \times 5}{1 \times 5} - \frac{48 \times 5}{1 \times 5} [/tex]
[tex] \frac{1}{5} + \frac{40}{5} - \frac{240}{5} [/tex]
[tex] \frac{1 + 40 - 240}{5} [/tex]
[tex] \frac{41 - 240}{5} [/tex]
[tex] - \frac{199}{5} [/tex]
[tex] - 39 \frac{4}{5} [/tex]
[tex]{\colorbox{purple}{\purple{\boxed{\colorbox{pink}{\blue{ {࿐Answer ࿐ by : ❀BrainlyElite14❀:･ﾟ}}}}}}}[/tex]
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